(5x^2-4)(x+2)=0

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Solution for (5x^2-4)(x+2)=0 equation: 


Simplifying
(5x2 + -4)(x + 2) = 0

Reorder the terms:
(-4 + 5x2)(x + 2) = 0

Reorder the terms:
(-4 + 5x2)(2 + x) = 0

Multiply (-4 + 5x2) * (2 + x)
(-4(2 + x) + 5x2 * (2 + x)) = 0
((2 * -4 + x * -4) + 5x2 * (2 + x)) = 0
((-8 + -4x) + 5x2 * (2 + x)) = 0
(-8 + -4x + (2 * 5x2 + x * 5x2)) = 0
(-8 + -4x + (10x2 + 5x3)) = 0
(-8 + -4x + 10x2 + 5x3) = 0

Solving
-8 + -4x + 10x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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